| Disregarding symettries (including reflections), there are 30 ways to label
the edges of a tetrahedron with distinct values. Letting these values be
n, n+1, n+2, ..., n+5, and using the equations of not 385, we get thirty
diophantine equations. An integer solution to any of these will yield a
tetrahedron with sides of consecutive integers, and having integral volume.
Note that the form of these equations is: 288V^2 = p(n), where p(n) is a
6th degree integer polynomial in n. Note that to find other solutions,
consideration of the equations in various modulii should prune the search
space.
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