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Conference rusure::math

Title:Mathematics at DEC
Moderator:RUSURE::EDP
Created:Mon Feb 03 1986
Last Modified:Fri Jun 06 1997
Last Successful Update:Fri Jun 06 1997
Number of topics:2083
Total number of notes:14613

581.0. "<><><> The fly and the two bicycles problem <><><>" by THEBUS::KOSTAS (Wisdom is the child of experience.) Thu Sep 18 1986 02:06

    Hello,
    
      The following is the "Fly and the two bicycles" problem:
    
    
         Two bicycles, 45  miles apart, are ridden towards each 
         other at the rates of  20  and  25  miles per hour. 
         A fly which goes  30  miles per hour, starts with one
         of the bicycles, flies towards the other, and back and
         forth, losing no time on the turns, until the cyclists
         meet.
   
         How many miles does the fly fly?
    
    
      Enjoy,
    
      Kostas G.
    
T.RTitleUserPersonal
Name
DateLines
581.1Ho hum....FDCV01::LOHMILLERThu Sep 18 1986 15:012
    30.
    
581.2re. .1THEBUS::KOSTASWisdom is the child of experience.Sat Sep 20 1986 23:1826
    re. .1
    
    yes, 
    
        since I never liked short answers, and I am allways interested
    in the method used to get to the solution I will elaborate a little
    more than "30."
    
    The problem of the fly and the bicycles is very puzzling if one
    starts to reckon the times of the fly's successive trips. But if
    we observe that the cyclists approach each other at the rate of
     (20 + 25) = 45  miles per hour, we see that it is just one hour
    before they meet, and in that time the fly will go just  30  miles.
    
    The problem is easily generalized. If we let  a  nd  b  be the rates
    of the cyclists,  m  the original distance, and  f  the rate of
    the fly, the cyclists will meet in  m/(a+b)  hours, and in that
    time the fly will fly a distance of
    
              mf
           ------- miles
            (a+b)
    
    -kgg
    
581.3How many times does fly change course ?RAYNAL::OSMANand silos to fill before I feep, and silos to fill before I feepMon Sep 22 1986 20:2510
For folks like myself, that solved the standard fly-between-bicycles
problem long ago, perhaps the following related problem might be
more challenging:

	How many times does the fly (assume length f)change course before
	the bicycles are less than or equal to f from each other, i.e.
	where the fly presumably gets mashed and the riders are about
	to crash, or the riders pass each other.

/Eric
581.4...and quite a bit of buzzing was heard just before the crashTSE::FONSECACaught peeking under the rug of life...Thu Sep 25 1986 18:392
I'm not sure about this, but if this is theoretical fly (no length)
wouldn't the number of direction changes be infinet?
581.5yesCACHE::MARSHALLbeware the fractal dragonThu Sep 25 1986 19:436
                                                   
                  /
                 (  ___
                  ) ///
                 /
    
581.6BEING::POSTPISCHILAlways mount a scratch monkey.Thu Sep 25 1986 20:417
    Re .4, .5:
    
    No.  The request was for the number of changes until a certain
    condition, not until the bicycles meet.
    
    
    				-- edp
581.7Who Needs A Floating Point Hotbox?DRUMS::FEHSKENSFri Apr 29 1988 19:2515
    There's an amusing anecdote about John von Neumann and this puzzle,
    related in Goldstein's book about the history of computing (actual
    title unreachable just now).  In this story it's two trains rather
    than two bicycles.
    
    After the problem is posed to him, von Neumann looks up at the ceiling
    for a moment and gives the answer.  The poser says "Ah, you know
    the trick."  Von Neumann says "What trick?"  "The one that allows
    you to avoid summing the infinite series."
    
    To which von Neumann replies, deadpan, "But I *did* sum the infinite
    series."
                                                                      
    len.