| > "If 12 oxen eat grass ( which is growing uniformly all the time )
> on 3 and 1/3 acres in 4 weeks, and if 21 oxen eat the grass
> on 10 acres in 9 weeks, how many oxen will it take to eat all
> the grass on 24 acres in 18 weeks?"
>
> Use the following notation:
>
> F = amount of Feed required by one ox per week
> B = amount of grass at the Beginning on an acre
> G = amount of grass Growing per week per acre
If O = # oxen
A = # acres
W = # weeks,
then eaten grass = beginning grass + newly grown grass
i.e. W * O * F = A * B + W * A * G
Move to two variables: x = B / F
y = G / F
W O = A x + W A y
Interpret .0: 48 = 3 1/3 x + 13 1/3 y
189 = 10 x + 90 y
Solve: x = 10.8 and y = .9
Answer: O = (A x + W A y) / W
= (24 * 10.8 + 18 * 24 * .9) / 18
= 36 oxen
John
|
| re. .-1
well done.
Now some more observations:
Without repeating the problem, we end up with two equations:
4 * (12) F = 10/3 * B + 10/3 * 4 G
9 * (21) F = 10 B + 10 (9G)
Multiplying the first equation by 63 and the second by 16 to
eliminate F we get
21 B + 84 G = 16 B + 144 G
and B = 12 G which means that the grass had been growing 12 weeks
before the oxen were turned in
Now substituting into one of the original equations gives
F = (210/189) G which means that an ox can eat all the grass
that grows on an acre in one and one-ninth
weeks. F = (10/9) G.
Enjoy,
-kgg
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