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Conference rusure::math

Title:Mathematics at DEC
Moderator:RUSURE::EDP
Created:Mon Feb 03 1986
Last Modified:Fri Jun 06 1997
Last Successful Update:Fri Jun 06 1997
Number of topics:2083
Total number of notes:14613

586.0. "Cube cut-up" by 26205::YARBROUGH () Wed Sep 24 1986 18:04

Here's a nice exercise in visualization.

A cube has 12 edges. You can group these in four identical sets of three,
looking something like /\_ , i.e. one along each coordinate axis with two
connections and two free ends. If you stretch saran-wrap or whatever around
each of these, you get four tetrahedra which can be put together to form
the general shape of the cube, except that some of the volume is not
included: the volume of each tetrahedron is 1/6 that of the cube. 

What simple extension can you make to each of the tetrahedra to form four 
identical shapes, each containing three full-length and mutually 
perpindicular edges connected as above, that will fill the cube completely? 
T.RTitleUserPersonal
Name
DateLines
586.1One try followsSTAR::BRANDENBERGCivilization is the progress toward a society of privacy.Wed Sep 24 1986 20:496

    Since the four tetrahedra won't cover two of the faces, I would
    add an extension from each connection/vertex to the center of the
    face in which it lies.
    
    					Monty
586.2Eh?26205::YARBROUGHThu Sep 25 1986 12:433
    That's not at all clear. Each vertex is part of three faces; each
    edge is part of two faces. I can't understand what you are trying
    to describe.
586.3CLT::GILBERTeager like a childThu Sep 25 1986 13:3914
    Note that there are two distinct ways of assigning those 4 "/\_"
    shapes to edges:


		aaaaaaaaaac    		aaaaaaaaaad    
		ab        cc   		ab        dd   
		a b       c c  		a b       d d  
		a  b      c  c 		a  b      d  d 
		a   bbbbbbbbbbb		a   bcccccccccc
		acccdcccccc   b		adddbdddddd   c
		 a  d      d  b		 a  b      c  c
		  a d       d b		  a b       c c
		   ad        db		   ab        cc
		    ddddddddddd		    bbbbbbbbbbc
586.4how I long for graphicsCACHE::MARSHALLbeware the fractal dragonThu Sep 25 1986 13:5327
          .----------.
         /          /|        a          b
    	.----------/ |        .----------.
        |          | |                   |
        |          | |                   |  d 
        |          | /                   | / 
        |          |/                    |/
        `----------'                     '
                                         c    
    
    connect: a-c,b-d,a-d to form the tetrahedron. Notice that half of
    the front face of the cube is the triangle a-b-c, similarly half
    the right face is triangle b-c-d. But the top surface (and the bottom
    surface) are not contained at all (except at two points).
    
    as I understand .1, disconnect the line a-d. Now place point 'e' in
    the center of the top surface, and point 'f' in the center of the
    bottom surface. Now, draw lines a-e,e-f,f-d. also, b-e, c-f, a-f,
    d-e. this results in an octohedron.
    
    I think this shape does meet the requirements of the puzzle.
                                                   
                  /
                 (  ___
                  ) ///
                 /
    
586.5ExactlySTAR::BRANDENBERGCivilization is the progress toward a society of privacy.Thu Sep 25 1986 14:371
    
586.6Here's a mental image26205::YARBROUGHThu Sep 25 1986 16:596
Right! One way of visualizing this construction is to run an imaginary 
rubber band from the top center of the cube: to a corner, down the edge, to 
the bottom center, and back up an adjacent edge to the top center. This 
outlines one quarter of the cube. Now rotate the top by 90 degrees and you 
have the figure of .4. There are also several other solutions; I like 
this one.
586.7CLT::GILBERTeager like a childFri Oct 03 1986 04:151
    Does the same 'extension' work for the other edge assignment given in .3?
586.8Two kinds of /\_'sMODEL::YARBROUGHFri Oct 03 1986 11:4214
>    Does the same 'extension' work for the other edge assignment given in .3?

No. The 'other' (left) alternative in .3 does not conform to the problem 
definition in .0, since in that diagram not all the /\_'s are congruent;
two are left-handed, two are right-handed. 

In case you need a definition: pick up a /\_ by the middle segment so the 
ends hang down with one end close to you. If the nearest bend is to the 
left it is left-handed. Viewed from above:

	Left	      Right
	 /		\
	 \		/
	 /		\