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Conference rusure::math

Title:Mathematics at DEC
Moderator:RUSURE::EDP
Created:Mon Feb 03 1986
Last Modified:Fri Jun 06 1997
Last Successful Update:Fri Jun 06 1997
Number of topics:2083
Total number of notes:14613

1680.0. "Olympiad Corner No. 131, 13" by RUSURE::EDP (Always mount a scratch monkey.) Mon Oct 26 1992 12:38

    For an acute triangle ABC, M is the midpoint of the segment BC, P is a
    point on the segment AM such that PM=BM, H is the foot of the
    perpendicular line from P to BC, Q is the point of intersection of the
    segment AB and the line passing through H that is perpendicular to PB,
    and finally R is the point of intersection of the segment AC and the
    line passing through H that is perpendicular to PC.  Show that the
    circumcircle of triangle QHR is tangent to the side BC at the point H.
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1680.13D::ROTHGeometry is the real life!Mon Oct 26 1992 16:055
    >>                   -< Olympiad Corner No. 131, 13 >-

    That sounds like the kind of problem Stan would come up with.

    - Jim
1680.2CSC32::D_DERAMODan D'Eramo, Customer Support CenterMon Oct 26 1992 17:343
    Can you post a diagram? :-)
    
    Dan