| 4, 8, 7, 5, 10, 11, 13, 8, 7, 14, ...
Spoiler follows -
19
The list is the sums of the digits in 2^(n+1), n = 1... = 4+0+9+6
- Lynn -
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| Good job. How about the following;
1, 4, 5, 7, 10, 17, ...
clue follows;
2**n gives;
2, 16, 32, 128, 1024, 131072, ...
|
| > 4, 8, 7, 5, 10, 11, 13, 8, 7, 14, ...
If you continue the process of summing digits you arrive at
4, 8, 7, 5, 1, 2, 4, 8, ...
or, starting at the beginning,
1, 2, 4, 8, 7, 5, ...
which curiously contains the same digits as the repeating decimal expansion
of 1/7 = .142857142857...
In fact .124875124875... = 125/1001 = 1
------------
8 + 1
-----
125
There are all sorts of funny things you can find here. Like
12 = 4+8 = 7+5,
124+875 = 999,
875-124 = 751
Or, modulo 9:
8-7 = 1
7-5 = 2
5-1 = 4
1-2 = 8
2-4 = 7
4-8 = 5
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| re .2:
What fun, I had to rediscover the pattern myself. Here's another clue
some 7 years later;
reverse the decimal representation of the powers of two
1, 2, 4, 8, 61, 23, 46, 821, 652, 215, 4201, 8402, 6904
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