| T.R | Title | User | Personal
Name | Date | Lines |
|---|
| 466.1 | just against the law is all... | ENGINE::ROTH | | Mon Apr 07 1986 02:35 | 7 |
| Algebra is supposed to be a noise-free information processing system;
however, dividing by zero sends any nonzero quantity to infinity, (at
least over R and C) and this causes a loss of information. This is why
one should not 'be allowed' to divide by zero during algebraic manipulation.
At any rate, its just not defined, whatever the field...
- Jim
|
| 466.2 | | CLT::GILBERT | Juggler of Noterdom | Mon Apr 07 1986 05:40 | 4 |
| %BAS-F-DIVBY_ZER, Division by 0
-BAS-I-USEPC_PSL, at user PC=001967E8, PSL=03C000A2
-SYSTEM-F-FLTDIV_F, arithmetic fault, floating divide by zero at PC=00197E8, PSL=03C000A2
-BAS-I-FROLINMOD, from line 10 in module NONAME
|
| 466.3 | mostly... | METOO::YARBROUGH | | Mon Apr 07 1986 12:33 | 2 |
| Disdain.
|
| 466.4 | It depends... | ERIS::CALLAS | Jon Callas | Tue Apr 08 1986 03:03 | 1 |
| on what you were looking for...
|
| 466.5 | And... | KBOV05::J_WOLFF | Julian Wolff | Tue Apr 08 1986 04:01 | 14 |
| Here what you get...
x = x
x^2 = x^2
x^2 - x^2 = x^2 - x^2
x ( x - x ) = (x + x) (x - x)
x = 2 x
1 = 2
So...
Julian.
|
| 466.6 | Here is what you get from Calreal | KEEPER::KOSTAS | Kostas G. Gavrielidis <o.o> | Tue Apr 08 1986 13:49 | 15 |
|
re. .2
here is one from calreal
$calreal
CALREAL> 1/0;
^
%CALREAL-E-003: ZERO DENOMINATOR IN DIVISION OPERATION
CALREAL> #
$
|
| 466.7 | Perfectly simple | NANUCK::PETERSEN | Some assembly required. | Tue Apr 08 1986 20:26 | 29 |
| Actually, the proposition that one divided by zero equals
infinity is easy to prove, using rotational mathematics:
(Please accept "oo" as the traditional symbol for infinity.)
We start with the well-known fact:
1
---- = 0
oo
Now, we rotate ninety degrees to get:
-18 = 0
Adding eight to both sides, we obtain:
-10 = 8
And, reversing the previous rotation (to normalize the equation)
we get the desired:
1
---- = oo
0
(Someone check my arithmetic, please.)
Theo
|
| 466.8 | The wrong answer ofter given for 1/O = oo. | THEBUS::KOSTAS | Kostas G. Gavrielidis <o.o> | Mon Apr 14 1986 17:08 | 25 |
| re. .7
Well you given the wrong answer I was looking for.
This is the kind of answer we find in some math books and is printed
as:
1
----- = oo
O
but a careful reading we find that this is an abbreviation for
something quite different from what it appears to be inticated.
"In-finite" means "no limit", and the "O" in the dinominator is
not a zero, like 2 - 2 = 0, but stands for a variable approaching
zero as its limit. The smaller it gets, the larger (without limit)
is its reciprocal. That is the meaning of 1/O = oo.
Note: The characters "oo" are used to inticate the symbol for
infinity.
Enjoy,
Kostas G.
|
| 466.9 | The detour sign approach. | THEBUS::KOSTAS | Kostas G. Gavrielidis <o.o> | Mon Apr 14 1986 17:14 | 14 |
| Hello,
On the original problem once again. The appearance of a zero
as a divisor or denominator should be regarded as a detour sign.
DO NOT FOLLOW THE USUAL ROUTE IN SUCH A CASE. This then requires
the redefinition of division. I will therefore request some ideas
as to how we define division that will take care the problem of
a division by zero.
I have a three step definition but I am interested to see other
ideas.
Kostas G.
|
| 466.10 | Cross-reference | LATOUR::JMARTIN | Joseph A. Martin | Thu May 01 1986 14:52 | 3 |
| This discussion seems to have been taken up in RAINBW::MUSIC #144 under
the guise of piano tuning.
--Joe :-)
|