T.R | Title | User | Personal Name | Date | Lines |
---|
383.1 | | BEING::POSTPISCHIL | | Wed Nov 20 1985 20:16 | 7 |
| It's about 21.8 miles to work. This assumes the cup is cylindrical, the
surface of the Earth is a plane, the cup is positioned vertically throughout
the trip, and the coffee manages not to spill when you change from
acceleration to deceleration.
-- edp
|
383.2 | | R2ME2::GILBERT | | Thu Nov 21 1985 00:31 | 27 |
383.3 | | METOO::YARBROUGH | | Thu Nov 21 1985 12:03 | 3 |
| I think Peter has confused his constants. The coffee will sustain a 1g
horizontal acceleration, which is 9.8 m/s^2 or 32 f/sec^2, not 32m/s^2.
The result in .1 sounds right. - Lynn
|
383.4 | | REX::MINOW | | Thu Nov 21 1985 13:20 | 11 |
| Sorry to bring reality into the picture, but
1. You must compensate for Corolis forces.
2. You must compensate for Sun/Moon tides as your position changes.
3. At the instants when accelleration changes, you must compensate
for the kind of coffee and amount of sugar (or for the viscosity
of the fluid, if you want to be picky).
Have at it.
|
383.5 | | SPRITE::OSMAN | | Thu Nov 21 1985 14:34 | 24 |
| "Sorry to bring reality into the picture, but"
You all forgot to *drink* some of the coffee during the trip, which would
of course allow more accelaration.
No, only kidding, but it's interesting that when I asked my girlfriend this
puzzle, she brought that aspect up immediately, and I might mention she's not
very mathematically inclined.
When I formulated the problem, I forgot to consider deccelarating at all.
With the simple accelerate all the way case, I calculated an answer of
72 km. Do others agree ?
My formula is d = 1/2 * a * t**2. a = 10, t = 60*2, so
d = 1/2 * 10 * 120**2 = 5 * 14400 = 72000 m = 72 km.
By the way, I don't believe the cup need by cylindrical. For instance,
a cubical cup ought yield same answer, right ? However, perhaps only
certain orientations of the cubical cup are optimal. For instance,
intuitively, I'd say by symmetry that if face or edge is forward, we're
o.k., but what about intermediate rotations ? (obviously we need to hold
all coffee cups level though)
/Eric
|
383.6 | | TOOLS::YARBROUGH | | Thu Nov 21 1985 16:02 | 5 |
| re .5 - for two minutes it's 120 seconds, so 1/2 g t^2 is 4 times larger
than that, or 16*14400 ft.
A cube IS a cylinder. Any cylinder with central or front-back symmetry will
do.
|
383.7 | | TOOLS::STAN | | Thu Nov 21 1985 19:52 | 1 |
| "coreolis".
|
383.8 | | HARE::GILBERT | | Thu Nov 21 1985 20:18 | 27 |
383.9 | | ADVAX::J_ROTH | | Thu Nov 21 1985 20:21 | 1 |
| No, "Coriolis".
|
383.10 | | SPRITE::OSMAN | | Fri Nov 22 1985 13:14 | 14 |
| >re .5 - for two minutes it's 120 seconds, so 1/2 g t^2 is 4 times larger
>than that, or 16*14400 ft.
>
>A cube IS a cylinder. Any cylinder with central or front-back symmetry will
>do.
First of all, I think you're working in feet, and I'm working in metric.
Are both of our answers correct ?
Secondly, since when is a cube a cylinder ?? I thought a cylinder's definition
is a *circle* projected through space. Or is a cylinder really considered
by definition to be *anything* projected through space ?
/Eric
|
383.11 | | TURTLE::GILBERT | | Fri Nov 22 1985 16:02 | 1 |
| My dictionary has a definition for "cylinder", doesn't yours?
|
383.12 | | SPRITE::OSMAN | | Fri Nov 22 1985 17:59 | 1 |
| no
|
383.13 | | AJAX::CALLAS | | Fri Nov 22 1985 20:09 | 8 |
| Well, here's what mine says:
cyl-in-der n. 1. a. a surface generated by a straight line moving parallel
to a fixed straight line and intersecting a plane curve. b. a solid bounded
by two parallel planes and such a surface having a closed curve, esp. a circle.
2. Something shaped like a cylinder. 3. A chamber in which a piston moves.
4. The rotating chamber of a revolver that holds the cartidges.
|
383.14 | | BEING::POSTPISCHIL | | Fri Nov 22 1985 20:38 | 7 |
| Re .12:
I think you need a new dictionary. The JOYOFLEX file contains some comments
about various dictionaries.
-- edp
|
383.15 | | SPRITE::OSMAN | | Thu Dec 19 1985 14:17 | 3 |
| Please see note 412 for a related problem.
/Eric
|
383.16 | This is one for third graders! | 57151::KURLAND | A mere rental | Wed Dec 07 1988 16:01 | 11 |
| RE: .1
I assume edp's answer was correct for HIS ride to work
31.2 miles is correct for MY ride to work
I fell off my dinosaur when I first heard a problem similar to this.
Reread the original question!!!!
|