[Search for users] [Overall Top Noters] [List of all Conferences] [Download this site]

Conference rusure::math

Title:Mathematics at DEC
Moderator:RUSURE::EDP
Created:Mon Feb 03 1986
Last Modified:Fri Jun 06 1997
Last Successful Update:Fri Jun 06 1997
Number of topics:2083
Total number of notes:14613

316.0. "you're on the right track !" by SPRITE::OSMAN () Tue Jul 16 1985 13:40

I like math problems that attract the attention of people that basically
"don't like math".  For instance, puzzles without too many numbers in them,
or that SEEM like perhaps they demand algebra, or even paper, but actually
end up being fairly simple once reflected upon for a bit.

Sometimes when first heard, the following seems not to have ENOUGH numbers in
it !

	A hiker has ventured part way across a narrow railroad bridge,
	when he hears a train approaching the bridge from behind him at
	60 miles per hour !

	He quickly realizes that at his current speed of hiking, he
	may retreat to the beginning of the bridge, or proceed to the
	end, with either strategy allowing him to reach the
	respective ends of the bridge just as the train does, and thus
	narrowly avoiding disaster.

	How fast is he hiking ?

Who can supply the nicest graphics rendition of this problem for DEC
terminals ?

/Eric
T.RTitleUserPersonal
Name
DateLines
316.1HARE::GILBERTTue Jul 16 1985 16:5414
If the bridge is 12 miles long, and that the hiker is 1/3 of the way across it,
and he travels at 20 mph, he can reach one end in 12 minutes, or the other in
24 minutes.  The difference in these times is the same as the train's transit
time, 12 minutes.

If he's 1/4 of the way across, and he travels at 30 mph, he can reach one end
in 6 minutes, or the other in 18 minutes.  Again, the difference is the same as
the train's transit time, so this, too, is a possible solution to the problem.

	"I knew a scout by the name of Jack,
	 Who took a hike on a railroad track.
	 The 8:15 came 'round the bend --
	 What kind of flowers you gonna send?"
                      
316.2SCOTTY::CCANTORTue Jul 16 1985 18:3612
	h = s(1-2f), where:

	h = hiking speed
	s = train speed
	f = fraction of bridge the hiker has crossed


	Since the answer is far from unique, I don't see that you have
supplied ENOUGH numbers.

-cjc

316.3SPRITE::OSMANTue Jul 16 1985 20:1312
Gee, it sure is a bit embarrassing in here.

Now that you've pointed it out (it's been several years since I heard
the original problem), I guess there IS another number.  It was
stated in the original problem that:

	The hiker is a third of the way across the bridge when he hears
	the train.

Sorry about the inaccuracy !

/Eric
316.4EIFFEL::BRETTTue Jul 16 1985 21:053
Wow!  20 mph!  That hiker sure can travel - most only do 2.5 to 3!

/Bevin
316.5SPRITE::OSMANThu Jul 18 1985 18:033
Imagine being in that predicament (i.e. real narrow bridge, not room for
both of you).  You might compete with that speed too !