[Search for users] [Overall Top Noters] [List of all Conferences] [Download this site]

Conference rusure::math

Title:Mathematics at DEC
Moderator:RUSURE::EDP
Created:Mon Feb 03 1986
Last Modified:Fri Jun 06 1997
Last Successful Update:Fri Jun 06 1997
Number of topics:2083
Total number of notes:14613

248.0. "middle of sequence solicited" by SPRITE::OSMAN () Mon Mar 25 1985 13:34

I'm thinking of a sequence that starts with

	41  44  71  77  104  107 . . .

The sequence ends with

	. . . 1034  1040  1067  1070

What's the whole sequence ?
T.RTitleUserPersonal
Name
DateLines
248.1SPRITE::OSMANMon Apr 01 1985 15:204
Hint:

	There are exactly 24 numbers in the whole sequence.

248.2LATOUR::JMUNZERTue Apr 02 1985 21:078
The problem gets easier when the numbers in the sequence are multiplied by 3:

	0123  0132  0213  0231  0312  0321 ...

	... 3102  3120  3201  3210

So the sequence is the set of decimal numbers which are permutations of
{0, 1, 2, 3}, divided by three.
248.3SPRITE::OSMANWed Apr 03 1985 15:067
Congratulations.  That's it !

I'm kind of curious whether nobody else figured it out until my hint, OR
if some people did but thought it was so simple they'd wait and give
others a chance, OR people found the problem unmotivating to work on.

Thanks for responding.
248.4LATOUR::JMUNZERWed Apr 03 1985 16:375
Well I needed the hint.  The differences (in decimal: 3, 27, 6, 27, ...)
suggested some sort of counting in some radix, but it took your hint (4!)
to focus the search.

Thank you for the problem.
248.5FUTBAL::GILBERTWed Apr 03 1985 23:431
I'd also persued the radix approach, with no success.