| Title: | -={ H A C K E R S }=- |
| Notice: | Write locked - see NOTED::HACKERS |
| Moderator: | DIEHRD::MORRIS |
| Created: | Thu Feb 20 1986 |
| Last Modified: | Mon Aug 03 1992 |
| Last Successful Update: | Fri Jun 06 1997 |
| Number of topics: | 680 |
| Total number of notes: | 5456 |
I just had a support call from a customer who is hacking DCL lexical
functions. (I don't know why he isn't using a programming language,
but ... ).
I've given his question some thought, but I don't really see a way to do
it. Maybe somebody could throw some light on it for me.
He wants to convert 32-bit quantity consisting of 3 bytes plus an
ascii character into an integer plus the character.
He says that the function he wants is "f$cvui applied to an integer
instead of a string".
Can DCL be tricked into regarding the integer as a string somehow?
(Then he can just use f$cvui).
Ideas?
| T.R | Title | User | Personal Name | Date | Lines |
|---|---|---|---|---|---|
| 389.1 | I think it can be done | CADSYS::SLATER | Ken Slater | Fri Jan 23 1987 11:41 | 13 |
If I understand the question properly, you have an integer in a DCL
symbol which is in reallity 3 bytes of an integer and a character.
The customer wants to seperate them.
I suggest reading the VMS V4.4 DCL Concepts manual, especially sections
5.9 and 5.10, for ideas on how to solve this problem.
Assuming the character is the last byte:
$ integer_part = composite_longword/256
$ character[0,8] := f$cvui(composite_longword,0,8)
This is just off the top of my head and untested, but it may give you
the ideas you are looking for...Ken
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| 389.2 | Modest proposal | MDVAX3::COAR | A wretched hive of bugs and flamers. | Wed Dec 02 1987 15:57 | 14 |
Actually, it sounds more as though he's got 32 bits that look something
like
$ A = %X00002341 ! binary 35 plus letter A
If this is the case, he can separate the parts by using
$ BIN = (A .AND. %XFFFFFF00) / 256
$ CHR = ""
$ CHR[0,8]= A - (BIN * 256)
How's that?
#ken :-)}
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