T.R | Title | User | Personal Name | Date | Lines |
---|
1152.1 | | KOBAL::GILBERT | Ownership Obligates | Tue Nov 21 1989 19:58 | 13 |
1152.2 | Cat & Mouse | DEC25::ROBERTS | Reason, Purpose, Self-esteem | Wed Nov 22 1989 14:20 | 17 |
| RE: 1152.1
"I assume that what you really want has all the 'drag' at B, not along
the length of the string."
Quite right.
Another way to express the problem is:
Mickey Mouse leaves his house and takes a walk due east. Sylvester the
cat, initially one unit north of Mickey, stalks him, remaining exactly
1 unit distant. At any instant, Sylvester is always moving directly
toward Mickey. Where is Sylvester when Mickey is t units away from
home?
/Dwayne
|
1152.3 | Looked it up | AKQJ10::YARBROUGH | I prefer Pi | Wed Nov 22 1989 17:58 | 10 |
| The equation of a tractrix symmetric about the y-axis and asymptotic to the
x-axis is
2 2 2 2
x = (a arccosh(a/y)-sqrt(a -y ))
where a>0 is the height of the curve above the x-axis at x=0.
(From Bronshtein & Semendyayev, 'Handbook of Mathematis', p.85).
Yeah, it's messy.
Lynn
|
1152.4 | | DEC25::ROBERTS | Reason, Purpose, Self-esteem | Wed Nov 22 1989 19:33 | 4 |
| Is anyone able to derive it?
/Dwayne
|
1152.5 | Derive by showing it works? | VMSDEV::HALLYB | The Smart Money was on Goliath | Wed Nov 22 1989 19:34 | 1 |
| Should you be able to differentiate .3 and get .1 ?
|
1152.6 | | AITG::DERAMO | Don't stop short of the peak! | Wed Nov 22 1989 20:02 | 6 |
| >> Should you be able to differentiate .3 and get .1 ?
I believe so, with a = 1. If not, one of them is
probably wrong.
Dan
|
1152.7 | | KOBAL::GILBERT | Ownership Obligates | Wed Nov 22 1989 20:09 | 2 |
| Yes, that fits the equation in .1 nicely. Note that it's most easily
done with x treated as a function of y.
|