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Conference rusure::math

Title:Mathematics at DEC
Moderator:RUSURE::EDP
Created:Mon Feb 03 1986
Last Modified:Fri Jun 06 1997
Last Successful Update:Fri Jun 06 1997
Number of topics:2083
Total number of notes:14613

979.0. "Extreme value problem" by KIRKWD::FRIEDMAN () Sun Nov 27 1988 02:14

    Could someone explain how one would go about solving the following
    extreme function value problem:
    
    A steel girder 27 ft long is moved horizontally along a passageway
    8 ft wide and into a corridor at right angles to the passageway.
    How wide must the corridor be for the girder to go around the
    corner.  Neglect the horizontal width of the girder.
    
    
    
    Thank you very much.
T.RTitleUserPersonal
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979.1BEING::POSTPISCHILAlways mount a scratch monkey.Mon Nov 28 1988 18:0123
    Re .0:
    
    Consider two points, one the corner and one the point where the ladder
    touches the other side of the 8 foot passage.  Our initial condition
    has one end of the ladder at the corner and the other at its farthest
    down the 8 foot passage.  The angle from the ladder to the wall is O,
    where O = arc sin(8/29).
    
    As we move the ladder up the passage, a bit of it sticks out.  Now the
    portion of the ladder still in the 8 foot passage is the hypotenuse of
    a right triangle, where O is another angle and the length of the
    opposite leg is 8 feet.  So the length of that portion of the ladder is
    8 / sin(O).  The length of the rest of the ladder is 29 - 8/sin(O).
    
    The horizontal amount by which that rest of the ladder sticks out
    beyond the corner is cos(O) * (29-8/sin(O)).
    
    Take the derivative of that, solve for a zero value between arc
    sin(8/29) and a right angle, and put the result back in the above
    formula.  The length is about 12.685.
    
    
    				-- edp
979.229?KIRKWD::FRIEDMANMon Nov 28 1988 22:262
    Where does the "29" come from?  Could you mean "27" in all those
    expressions?
979.3BEING::POSTPISCHILAlways mount a scratch monkey.Tue Nov 29 1988 12:066
    Re .2:
    
    Yes, they should all be 27, which changes the answer to about 11.18.
    
    
    				-- edp
979.45**1.5CLT::GILBERTMultiple inheritence happensTue Nov 29 1988 13:4887
979.5CLT::GILBERTMultiple inheritence happensTue Nov 29 1988 17:036
>	               2/3      3/2
>	x = - w ( (l/w)    - 1 )   .		(a pretty result)

Even nicer:
	         2/3    2/3  3/2
	x = - ( l    - w    )   .
979.6Moving sofasAKQJ10::YARBROUGHI prefer PiTue Nov 29 1988 18:3810
Here's a related problem that is somewhat easier to solve: 

A building has two hallways meeting at right angles, each 6 feet wide. If all 
sofas are 3 feet wide, what's the longest sofa that can be moved from one 
hallway to the other (while being kept level)?

In this version you can take advantage of symettry to simplify the
solution. Only quadratics are involved.

Lynn Yarbrough 
979.73-DAITG::DERAMODaniel V. {AITG,ZFC}:: D'EramoTue Nov 29 1988 21:155
     re .6
     
     How high is the ceiling?
     
     Dan
979.8but the cushions will fall outAKQJ10::YARBROUGHI prefer PiWed Nov 30 1988 14:157
No, no, I said *level*. No fair tipping it.

Actually, the length of sofa in this problem actually exceeds the height of 
most ceilings (8 ft.) but let's leave the 3-d case as an exercise for the
ambitious reader.

Lynn