Title: | Mathematics at DEC |
Moderator: | RUSURE::EDP |
Created: | Mon Feb 03 1986 |
Last Modified: | Fri Jun 06 1997 |
Last Successful Update: | Fri Jun 06 1997 |
Number of topics: | 2083 |
Total number of notes: | 14613 |
they just increased the lenght of my password from 6 to 12 characters. i can use 0-9, a-z, ., and _. how many combinations, or possible passwords are there??? how do you figure it? dale
T.R | Title | User | Personal Name | Date | Lines |
---|---|---|---|---|---|
861.1 | It's a lot | AKQJ10::YARBROUGH | Why is computing so labor intensive? | Mon Apr 11 1988 13:49 | 14 |
> they just increased the lenght of my password from 6 to 12 characters. > i can use 0-9, a-z, ., and _. how many combinations, or possible > passwords are there??? how do you figure it? Assuming a password can be of any length from 1 to 12; for each length L there are 37 possible characters at each position, so 37^L possible choices. The total is SUM(37^L, L=1..12) = SUM(37^L, L=0..12) - 1 = (37^13-1) / (37-1) - 1 = 6765 81178 37800 36260 Lynn Yarbrough | |||||
861.2 | more... | DPDMAI::FRAMELI | Tue Apr 12 1988 07:41 | 5 | |
unfortunately my password has to be 12 characters, will this change things? dale | |||||
861.3 | A little smaller | AKQJ10::YARBROUGH | Why is computing so labor intensive? | Tue Apr 12 1988 15:27 | 1 |
In that case the number is simply 37^12, or 6582 95200 58400 35281. |